C programming reverse number

Reverse a number in C:

The code for reversing a number in C is:

#include <stdio.h>
int  main()
{
int  num;
int  reversedNum = 0;
int  remainder;
printf("Enter an integer: ");
scanf("%d", & amp; num);
while (num != 0)
{
  remainder = num % 10;

  reversedNum = reversedNum * 10  + remainder;

  num = num / 10;

}
printf("Reversed Number = %d", reversedNum);
return  0;
}

The inputs and outputs for the above code are:

Enter an integer: 1234

Reversed Number = 4321

Enter an integer: 456

Reversed Number = 654

Enter an integer: 905

Reversed Number = 509

We have created the variable num to store the user input and the variable reversedNum to store the reverse of the number input by the user.
The while loop runs until num is not equal to 0.
In each iteration, we calculate the remainder when num is divided by 10. The value of num is then reduced by 10 times.
At the end of the loop, we get the reversed number.

When we input 1234 for the above code, all the intermediate steps will be:

Enter an integer: 1234

Before iteration:

num: 1234

During iteration:

remainder: 4

reversedNum: 4

num: 123

remainder: 3

reversedNum: 43

num: 12

remainder: 2

reversedNum: 432

num: 1

remainder: 1

reversedNum: 4321

num: 0

After iteration:

Reversed Number = 4321